Super simple and elegant O(n) python solution (with comments)

#1 
class Solution:
# @param A : tuple of integers
# @return an integer
def longestConsecutive(self, arr):
    numSet=set(arr)
    maxCount=0
    for num in arr:
        if not num in numSet: #already tested before
            continue
        count=1
        for step in [1,-1]:#try forwad and backward
            currentNum=num+step
            while currentNum in numSet: #keep moving till currentNum not found
                numSet.remove(currentNum)
                count+=1
                currentNum+=step
        maxCount=max(maxCount,count)
    return maxCount