This can be much simple code for this question

[ayush-sharma_603]

string Solution::addBinary(string A, string B) {

string result = “”;
int s = 0;

int i = A.size() - 1, j = B.size() - 1; 
while (i >= 0 || j >= 0 || s == 1) 
{ 
    
    s += ((i >= 0)? A[i] - '0': 0); 
    s += ((j >= 0)? B[j] - '0': 0); 

    
    result = char(s % 2 + '0') + result; 

    
    s /= 2; 

    i--; j--; 
} 
return result; 

}