int Solution::maxProfit(const vector<int> &A) {
if(A.size()==0||A.size()==1) return 0;
int prediff=INT_MIN,prev_max_profit=0,max_profit=0;
for(int i=1;i<A.size();i++)
{
prediff=max(prediff,-A[i-1]);
max_profit=max(prev_max_profit,A[i]+prediff);
prev_max_profit=max_profit;
}
return max_profit;
}
Very Easy and Short C++ Solution O(1) space and O(N) time
msbobby87
#1